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Acetic acid is a weak acid. The molar conductances of 0.05 M acetic acid at 25 ° C is 7.36 S c m 2 m o l - 1 . If its Λ m ∞ is 390.72 S c m 2 m o l - 1 . The value of equilibrium constant is

Options

  1. A1.8 × 1 0 - 5
  2. B1.8 × 1 0 - 7
  3. C3.6 × 1 0 - 5
  4. D5.4 × 1 0 - 5

Correct answer

A. 1.8 × 1 0 - 5

Step-by-step solution

α c = Λ m e / Λ m ∞ = 7.36 / 390.72 = 0.019 So K α = [ C H 3 C O O - 1 ( a q ) ] [ H 3 O + ( a q ) ] [ C H 3 C O O H ] = C α 2 1 - α ≈ C α 2 = 1.8 × 1 0 - 5

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