The measured voltage of the cell, Pt(s) H 2 (1 .0 atm) H + (aq)| Ag + (1 .0 M) Ag(s) is 1 .02 V at 25 o C . Given E c e l l o is 0 .80 V , calculate the pH of the solution.

Step-by-step solution

E cell = E cell o − 0 .059 n log [H + ] 2 [Ag + ] 2 = E cell o − 0 .059 × 2 2 log H + Ag + E cell o − 0 .059 × log H + 1 = E cell o + 0 .059 ( − log[H + ]) 1 = E cell o + 0 .059 pH So pH = E cell − E cell o 0 .059 = 1 .02 − 0 .80 0 .059 = 3 .73