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When two half-cells of electrode potential of E 1 o and E 2 o are combined to form a cell of electrode potential E 3 o ( n 1 , n 2 , n 3 are the number of electrodes exchanged in first, second and third half-cell reactions), then

Options

  1. AE 3 o = E 1 o + E 2 o
  2. BE 3 o = E 2 o - E 1 o
  3. CE 3 o = n 1 E 1 o + n 2 E 2 o n 3
  4. DE 3 o = n 1 E 1 o - n 2 E 2 o n 3 2

Correct answer

C. E 3 o = n 1 E 1 o + n 2 E 2 o n 3

Step-by-step solution

As E ° is non additive but Δ G ° is additive Δ G 3 o = Δ G 1 o + Δ G 2 o - n 3 F E 3 o = - n F E 1 o - n 2 F E 2 o E 3 o = n 1 E 1 o + n 2 E 2 o n 3

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