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Efficiency of the following cells is 84%. A ( s ) + B 2 + ( a q ) ⇌ A 2 + ( a q ) + B ( s ) ; Δ H = - 285 kJ Then the standard electrode potential of the cell will be

Options

  1. A1.20 V
  2. B2.40 V
  3. C1.10 V
  4. D1.24 V

Correct answer

D. 1.24 V

Step-by-step solution

Efficiency = Δ G ° Δ H ° = - n F E ° Δ H ° 0.84 = - 2 × E ° × 96500 - 285 × 1000 E ° = + 1.24 V .

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