NTA Abhyas NEET2020ChemistryElectrochemistryPractice
Z n | Z n S O 4 ( 0.01 M ) | | C u S O 4 ( 1.0 M ) | C u is a Daniel cell. The ‘emf ’ of this cell at 298K is E 1 . when the concentration of Z n S O 4 changes to 1.0 M and that of C u S O 4 is 0.01 M, the ‘emf ’ changed to E 2 . What is the relationship between E 1 and E 2
Options
- AE 2 = 0 ≠ E 1
- BE 1 > E 2
- CE 1 < E 2
- DE 1 = E 2
Correct answer
B. E 1 > E 2
Step-by-step solution
E 1 = E o - 0.0591 2 l o g 0.01 1 = E o + 0.0591 2 × 2 E 2 = E o − 0.0591 2 log 1 0.01 = E o − 0.0591 2 × 2 ∴ E 1 > E 2 .