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The resistance of 0.01 N NaCl solution at 25 ° C is 200 ohm. Cell constant of the conductivity cell is unity. The equivalent conductivity of the solution is

Options

  1. A500 o h m - 1 c m 2 e q - 1
  2. B5 o h m - 1 c m 2 e q - 1
  3. C250 o h m - 1 c m 2 e q - 1
  4. DNone

Correct answer

A. 500 o h m - 1 c m 2 e q - 1

Step-by-step solution

K = 1 R × cell constant Here K = specific conductance = 1 200 × 1 = 5 × 1 0 - 3 o h m - 1 c m - 1 λ v = K × V N = 5 × 1 0 - 3 × 100 × 1000 500 o h m - 1 c m 2 e q - 1

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