NTA Abhyas NEET2020ChemistryElectrochemistryPractice
Calculate the equivalent conductance of the electrolytic cell. Given: l/a = 0 .5 cm − 1 , R = 50 ohm, N = 1 .0
Options
- A10 ohm − 1 cm 2 g eq − 1
- B20   ohm − 1   cm 2   g   eq − 1
- C300   ohm − 1   cm 2   g   eq − 1
- D100   ohm − 1   cm 2   g   eq − 1
Correct answer
A. 10 ohm − 1 cm 2 g eq − 1
Step-by-step solution
l/a = 0 .5 cm − 1 , R = 50 ohm ρ = Ra l = 50 0.5 = 100 Λ = k × 1000 N = 1 ρ × 1000 N = 1 100 × 1000 1 10   ohm − 1   cm 2   g   eq − 1