What is the molar conductance in S cm 2 mol - 1 of 1 M solution of acetic acid; if the resistance of that solution is 250 ohm and cell constant is equal to 1 . 15 cm - 1 ?

Step-by-step solution

Using the formula, κ   ( conductivity ) = Cell   constant R = 1 .15 250   S   cm - 1 Now, using the relation between molar conductance, conductivity and molarity of the solution, Λ m   S   cm 2   mol - 1 = K   S   cm - 1 × 1000   cm 3 / L molarity   ( mol / L ) Λ m = 1 .15 250 × 1000 1 Λ m = 4 .6   S   cm 2   mol - 1 .