The equivalent conductance of a 0 .2 N solution of an electrolyte was found to be 200 Ω − 1 cm 2 eq − 1 . The cell constant of the cell is 2 cm − 1 . The resistance of the solution is

Step-by-step solution

Λ v = 200   Ω − 1 cm 2 eq − 1 C N = 0.2   N,   cm − 1 K = Λ v × C N 1000 = 200 × 0.2 1000 × 10 = 1 25 Ω - 1 c m - 1 R = 1 K . l a = 25 × 2 = 50 Ω .