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The values of Λ e q ∞ for N H 4 C l , NaOH and NaCl are, respectively, 149.74, 248.1 and 126.4 o h m - 1 c m 2 e q - 1 . The value of Λ e q ∞ N H 4 O H is in ohm − 1 cm − 2 eq − 1

Options

  1. A371.44
  2. B271.44
  3. C71.44
  4. DIt cannot be calculated from the data given

Correct answer

B. 271.44

Step-by-step solution

Λ e q ∞ for N H 4 C l can be find out by the relation given below Λ e q o or Λ ∞ ( N H 4 O H ) = Λ ∞ e q ( N H 4 C l ) + Λ ∞ e q ( N a O H ) - Λ ∞ e q ( N a C l ) = ( 149.74 + 248.1 - 126.4 ) = 271.44 ohm − 1 cm 2 eq − 1

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