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Calculate the volume of O 2 liberated at STP by passing 5 A current for 193 sec through acidified water:

Options

  1. A56   mL
  2. B112   mL
  3. C158   mL
  4. D965   mL

Correct answer

A. 56   mL

Step-by-step solution

As per the first law of electrolysis, The mass deposited or volume liberated at the electrode is directly proportional to the charge passing between the electrode. m = ZQ Where Z = E F (electrovalent equivalent) Q = i × t . mass of O 2 =   E × i × t F (Where F = 96500   C ) = 8 × 5 × 193 96500   g = 0 . 08   g ∵ At S TP , volume of 32   g   O 2   =   22400   mL ∴ The volume of 0 . 08   g   O 2 = 22400 × 0 . 08 32 = 56 &

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