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NTA Abhyas NEET2020Chemistryp Block Elements (Group 13 & 14)Practice

The reaction of H 3 N 3 B 3 C l 3 (A) with L i B H 4 in tetrahydrofuran gives inorganic benzene (B). Further, the reaction of (A) with (C) leads to H 3 N 3 B 3 ( M e ) 3 . Compounds (B) and (C) respectively, are

Options

  1. ABorazine and MeBr
  2. BBoron nitride and MeBr
  3. CDiborane and MeMgBr
  4. DBorazine and MeMgBr

Correct answer

D. Borazine and MeMgBr

Step-by-step solution

Here B is Borazine and C is MeMgBr. The reactions are as follows B 3 N 3 H 3 Cl 3 A + LiBH 4 → B 3 N 3 H 6 B Inorganic Benzene or Borazine B 3 N 3 H 3 Cl + MeMgBr C → B 3 N 3 H 3 CH 3 3 + 3 MgBrCl

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