NTA Abhyas NEET2020Chemistryp Block Elements (Group 13 & 14)Practice
The reaction of H 3 N 3 B 3 C l 3 (A) with L i B H 4 in tetrahydrofuran gives inorganic benzene (B). Further, the reaction of (A) with (C) leads to H 3 N 3 B 3 ( M e ) 3 . Compounds (B) and (C) respectively, are
Options
- ABorazine and MeBr
- BBoron nitride and MeBr
- CDiborane and MeMgBr
- DBorazine and MeMgBr
Correct answer
D. Borazine and MeMgBr
Step-by-step solution
Here B is Borazine and C is MeMgBr. The reactions are as follows B 3 N 3 H 3 Cl 3 A + LiBH 4 → B 3 N 3 H 6 B Inorganic Benzene or Borazine B 3 N 3 H 3 Cl + MeMgBr C → B 3 N 3 H 3 CH 3 3 + 3 MgBrCl