NTA Abhyas NEET2020Chemistryp Block Elements (Group 13 & 14)Practice
Consider the following dioxide of group 14 1 . C O 2 2 . S i O 2 3 . G e O 2 4 . S n O 2 5 . P b O 2 The basicity of the dioxide alters in the order
Options
- AC O 2 > S i O 2 > G e O 2 > S n O 2 > P b O 2
- BC O 2 < S i O 2 < G e O 2 < S n O 2 < P b O 2
- CC O 2 < S i O 2 < G e O 2 < P b O 2 < S n O 2
- DC O 2 < S i O 2 < S n O 2 < P b O 2 < G e O 2
Correct answer
B. C O 2 < S i O 2 < G e O 2 < S n O 2 < P b O 2
Step-by-step solution
The basicity of the dioxide alters in the order C O 2 < S i O 2 < G e O 2 < S n O 2 < P b O 2 The basicity increases on moving down the group. Thus, C O 2 and S i O 2 are purely acidic. G e O 2 is not as strongly acidic as S i O 2 . It is weakly acidic and weakly basic. S n O 2 and P b O 2 are definitely amphoteric.