NTA Abhyas NEET2020Chemistryp Block Elements (Group 13 & 14)Practice
The dissolution of A l ( O H ) 3 by a solution of N a O H results in the formation of:
Options
- A[ A l ( H 2 O ) 4 ( O H ) 2 ] +
- B[ A l ( H 2 O ) 3 ( O H ) 3 ]
- C[ A l ( H 2 O ) 2 ( O H ) 4 ] -
- D[ A l ( H 2 O ) 6 ( O H ) 3 ]
Correct answer
C. [ A l ( H 2 O ) 2 ( O H ) 4 ] -
Step-by-step solution
A l ( O H ) 3 + N a O H ( s o l u t i o n ) → [ A l ( H 2 O ) 2 ( O H ) 4 ] Θ or N a A l O 2 .