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NEETPhysicsMotion in One Dimension

The velocity-time graph of a body moving in a straight line is shown in figure. The ratio of displacement and distance travelled by the body in time 0 to 10 s is

Options

  1. A1 : 1
  2. B1 : 2
  3. C1 : 3
  4. D1 : 4

Correct answer

C. 1 : 3

Step-by-step solution

Area of upper rectangles, which will give us magnitude of the area under the velocity-time graph, A 1 = 8 × 2 + 4 × 4 = 32 Area of lower rectangles, which will give us magnitude of the area under the velocity-time graph, A 2 = 4 × 2 + 4 × 2 = 16 Therefore, Displacement = A 1 - A 2 = 32 - 16 = 16 Distance = A 1 + A 2 = 32 + 16 = 48 Hence, the required ratio would be = 16 48 = 1 3

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