The displacement x of a particle in a straight line motion is given by x=1-t-t^2 . The correct representation of the motion is

Step-by-step solution

If we differentiate the equation of motion, x=1-t-t^2 w.r.t. time, we get velocity. v= d x d t =-1-2 t Comparing with v=u+a t , we have u=-1 ~ms ⁻¹ and a=-2 ~ms ⁻² At t=0, x=1 ~m . Then, u and a both are negative. Hence, x -coordinate of particle will go on decreasing.