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NEET
Exam
NEET
Subject
Physics
Chapter
Motion in One Dimension

NEET · Physics · Motion in One Dimension

The displacement x of a particle in a straight line motion is given...

The displacement xx of a particle in a straight line motion is given by x=1−t−t2x=1-t-t^2. The correct representation of the motion isThe displacement x of a particle in a straight line motion is given by x=1-t-t^2 . The correct representation of theThe displacement x of a particle in a straight line motion is given by x=1-t-t^2 . The correct representation of theThe displacement x of a particle in a straight line motion is given by x=1-t-t^2 . The correct representation of theThe displacement x of a particle in a straight line motion is given by x=1-t-t^2 . The correct representation of the

Options

  1. AA ball is projected with kinetic energy E , at an angle of 60 ° to the horizontal. The kinetic energy of this ball at
  2. BA ball is projected with kinetic energy E , at an angle of 60 ° to the horizontal. The kinetic energy of this ball at
  3. CA ball is projected with kinetic energy E , at an angle of 60 ° to the horizontal. The kinetic energy of this ball at
  4. DA ball is projected with kinetic energy E , at an angle of 60 ° to the horizontal. The kinetic energy of this ball at

Correct answer

B. A ball is projected with kinetic energy E , at an angle of 60 ° to the horizontal. The kinetic energy of this ball at

Step-by-step solution

If we differentiate the equation of motion, x=1−t−t2x=1-t-t^2 w.r.t. time, we get velocity. v=dxdt=−\frac{d x}{d t}=-1-2 t Comparing with v=u+atv=u+a t, we have u=−1 ms−1u=-1 \mathrm{~ms}^{-1} and a=−2 ms−2a=-2 \mathrm{~ms}^{-2} At t=0,x=1 mt=0, x=1 \mathrm{~m}. Then, uu and aa both are negative. Hence, xx-coordinate of particle will go on decreasing.
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