Form the v - t graph shown, the ratio of distance to displacement in 25 s of motion is:

Step-by-step solution

The area under the velocity time graph gives the displacement. The area for t = 0 s to t = 25 s is ( A r e a ) = 1 2 × 5 × 10 + 5 × 10 + 1 2 × 30 × 5 + 1 2 × 20 × 5 - 1 2 × 20 × 5 ⇒ A r e a = 25 + 50 + 75 + 50 - 50 = 150 m Hence, the displacement = 150 m The distance is defined as the path taken by the object to travel from initial to final position. Also note that displacement is a vector quantity, but distance is a scalar quantity. Distance = 1 2 × 5 × 10 + 5 × 10 + 1 2 × 30 × 5 + 1 2 × 20 × 5 + 1 2 × 20 × 5 = (