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NEET
Exam
NEET
Subject
Physics
Chapter
Motion in One Dimension

NEET · Physics · Motion in One Dimension

A bullet is shot vertically downwards with an initial velocity of...

A bullet is shot vertically downwards with an initial velocity of 100ms−1100m{s}^{- 1} from a certain height. Within 10s10s, the bullet reaches the ground and instantaneously comes to rest due to the perfectly inelastic collision. The velocity-time curve for total time t=20st = 20s will be : (Take g=10ms−2g = 10m{s}^{- 2})A bullet is shot vertically downwards with an initial velocity of 100m s ^ - 1 from a certain height. Within 10s , theA bullet is shot vertically downwards with an initial velocity of 100m s ^ - 1 from a certain height. Within 10s , theA bullet is shot vertically downwards with an initial velocity of 100m s ^ - 1 from a certain height. Within 10s , theA bullet is shot vertically downwards with an initial velocity of 100m s ^ - 1 from a certain height. Within 10s , the

Options

  1. AA parallel plate capacitor of capacitance 90pF is connected to a battery of EMF 20V . If a dielectric material of
  2. BA parallel plate capacitor of capacitance 90pF is connected to a battery of EMF 20V . If a dielectric material of
  3. CA parallel plate capacitor of capacitance 90pF is connected to a battery of EMF 20V . If a dielectric material of
  4. DA parallel plate capacitor of capacitance 90pF is connected to a battery of EMF 20V . If a dielectric material of

Correct answer

A. A parallel plate capacitor of capacitance 90pF is connected to a battery of EMF 20V . If a dielectric material of

Step-by-step solution

As the upward direction is taken as positive, the velocity at t=0t = 0 is u=−100ms−1u = - 100m{s}^{- 1}.

As it is falling under gravity, its acceleration is constant and a=−10ms−2a = - 10m{s}^{- 2}.

Applying equation of motion for constant acceleration during the time of fall i.e., for 00 to 10s10s,

v=u+atv = u + at
⇒v=−100−10×10⇒ v = - 100 - 10 \times 10
⇒v=−200ms−1⇒ v = - 200m{s}^{- 1}

After 10s10s it hits the ground and remains at rest.

Therefore, option A is the correct representation.

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