NEET
Exam NEET
Subject Physics
Chapter Mechanical Properties of Solids NEET · Physics · Mechanical Properties of Solids
An equilateral triangle ABC is formed by two Cu rods AB and BC and...
An equilateral triangle ABC is formed by two Cu rods AB and BC and one Al rod. It is heated in such a way that temperature of each rod increases by ∆T. Find change in the angle ABC. [Coefficient of linear expansion for Cu is α1 ,Coeff. of linear expansion for Al is α2 ]
Options A d θ = ( 2 α 1 − α 2 ) Δ t 3 d\theta =\frac{\left( 2{{\alpha }_{1}}-{{\alpha }_{2}} \right)\Delta t}{\sqrt{3}} d θ = 3 ( 2 α 1 − α 2 ) Δ t B d θ = ( 2 α 1 + α 2 ) Δ t 3 d\theta =\frac{\left( 2{{\alpha }_{1}}+{{\alpha }_{2}} \right)\Delta t}{\sqrt{3}} d θ = 3 ( 2 α 1 + α 2 ) Δ t C d θ = 2 ( α 1 − α 2 ) Δ t 3 d\theta =\frac{2\left( {{\alpha }_{1}}-{{\alpha }_{2}} \right)\Delta t}{\sqrt{3}} d θ = 3 2 ( α 1 − α 2 ) Δ t D d θ = ( α 1 + α 2 ) Δ t 3 d\theta =\frac{\left( {{\alpha }_{1}}+{{\alpha }_{2}} \right)\Delta t}{\sqrt{3}} d θ = 3 ( α 1 + α 2 ) Δ t Correct answer C. d θ = 2 ( α 1 − α 2 ) Δ t 3 d\theta =\frac{2\left( {{\alpha }_{1}}-{{\alpha }_{2}} \right)\Delta t}{\sqrt{3}} d θ = 3 2 ( α 1 − α 2 ) Δ t
Step-by-step solution
Correct Option is : (C)
d θ = 2 ( α 1 − α 2 ) Δ t 3 d\theta =\frac{2\left( {{\alpha }_{1}}-{{\alpha }_{2}} \right)\Delta t}{\sqrt{3}} d θ = 3 2 ( α 1 − α 2 ) Δ t
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