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A stone of mass m is tied to an elastic string of negligible mass and spring constant k. The unstretched length of the string is L and has negligible mass. The other end of the string is fixed to a nail at a point P. Initially the stone is at the same level as the point P. The stone is dropped vertically from point P. Find the distance y from the top when the mass comes to rest for an instant, for the first time

Options

  1. Ay= ( kL-mg ) mgkL+ m ² g ² k
  2. By= ( kL+mg ) mgkL+ m ² g ² k
  3. Cy= ( kL+mg ) 2mgkL+ m ² g ² k
  4. Dy= ( kL-mg ) 2mgkL+ m ² g ² k

Correct answer

C. y= ( kL+mg ) 2mgkL+ m ² g ² k

Step-by-step solution

Correct Option is : (C) y= ( kL+mg ) 2mgkL+ m ² g ² k

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