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JIPMER 2015
Exam
JIPMER
Year
2015
Subject
Physics
Chapter
Mechanical Properties of Solids

JIPMER 2015 · Physics · Mechanical Properties of Solids

What is the change in the volume of 1.0 L kerosene, when it is...

What is the change in the volume of 1.0 L kerosene, when it is subjected to an extra pressure of 2.0×105Nm−22.0 \times 10^5 \mathrm{Nm}^{-2} from the following data? Density of kerosene =800 kg=800 \mathrm{~kg} m−3\mathrm{m}^{-3} and speed of sound in kerosene =1330 ms−1=1330 \mathrm{~ms}^{-1}.

Options

  1. A0.97 cm−30.97 \mathrm{~cm}^{-3}
  2. B0.66 cm−30.66 \mathrm{~cm}^{-3}
  3. C0.15 cm−30.15 \mathrm{~cm}^{-3}
  4. D0.59 cm−30.59 \mathrm{~cm}^{-3}

Correct answer

C. 0.15 cm−30.15 \mathrm{~cm}^{-3}

Step-by-step solution

As, we know that v=Rρv=\sqrt{\frac{R}{\rho}} where, k=k= bulk modulus of elasticity ⇒k=v2ρ=(1330)2×800N/m2 Also, k=F/AΔV/V⇒ΔV= pressure k=2×1051330×1330×800=0.15cm3\begin{aligned} \Rightarrow & k & =v^2 \rho=(1330)^2 \times 800 \mathrm{ N} / \mathrm{m}^2 \\ \text{ Also, } & k & =\frac{F / A}{\Delta V / V} \\ \Rightarrow & \Delta V & =\frac{\text{ pressure }}{k}=\frac{2 \times 10^5}{1330 \times 1330 \times 800} \\ & & =0.15 \mathrm{ cm}^3\end{aligned}
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