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NEET
Exam
NEET
Subject
Physics
Chapter
Nuclear Physics

NEET · Physics · Nuclear Physics

Match the following ( List-I List-II (a) n arrow p + (p) α-decay...

Match the following (
List-IList-II
(a)n \rightarrow p + \ldots(p)\alpha-decay
(b)p \rightarrow n + \ldots(q)Positron emission
(c)x-ray emission(r)\beta^{-} emission
(d){}^{226}_{88}Ra \rightarrow {}^{222}_{86}Rn + \ldots(s)K electron capture
)

Options

  1. A(\mathrm{a} \rightarrow \mathrm{r}, \mathrm{b} \rightarrow \mathrm{q}, \mathrm{c} \rightarrow \mathrm{q}, \mathrm{d} \rightarrow \mathrm{s})
  2. Ba (\rightarrow \mathrm{q}, \mathrm{b} \rightarrow \mathrm{r}, \mathrm{c} \rightarrow \mathrm{s}, \mathrm{d} \rightarrow \mathrm{p})
  3. C(\mathrm{a} \rightarrow \mathrm{r}, \mathrm{b} \rightarrow \mathrm{q}, \mathrm{c} \rightarrow \mathrm{s}, \mathrm{d} \rightarrow \mathrm{p})
  4. Da (\rightarrow) q, b (\rightarrow) s, c (\rightarrow) r, d (\rightarrow) p

Correct answer

C. (\mathrm{a} \rightarrow \mathrm{r}, \mathrm{b} \rightarrow \mathrm{q}, \mathrm{c} \rightarrow \mathrm{s}, \mathrm{d} \rightarrow \mathrm{p})

Step-by-step solution

a: (n→p+…\mathrm{n} \rightarrow \mathrm{p +} \ldots) This represents the decay of a neutron into a proton, which is (β\beta)-emission ((r\mathrm{r})). - b: p (→n+\rightarrow \mathrm{n +})... This represents the decay of a proton into a neutron, which can be Positron emission (q). - c: x-ray emission X-ray emission is often associated with K electron capture (s), where an inner electron is captured by the nucleus, leading to characteristic X-rays. - d: This is an example of a-decay (p), as the atomic number decreases by 2 and the mass number by 4. Matching these gives: a→r,b→q,c→s,d→pa → r, b → q, c → s, d → p. This corresponds to option (3).
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