NEETPhysicsNuclear Physics
Match the mass quantities in List-I with their corresponding energy equivalents in List-II. List-I List-II (A) 1 kg (I) 931.5 MeV (B) 1 mg (II) 0.511 MeV (C) 1 atomic mass unit (u) (III) 9 10¹⁶ J (D) Mass of an electron (IV) 9 10¹⁰ J Choose the correct answer from the options given below:
Options
- A(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
- B(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
- C(A)-(III), (B)-(IV), (C)-(II), (D)-(I)
- D(A)-(III), (B)-(I), (C)-(IV), (D)-(II)
Correct answer
A. (A)-(III), (B)-(IV), (C)-(I), (D)-(II)
Step-by-step solution
According to Einstein's mass-energy equivalence, E = mc^2 . (A) For m = 1 kg : E = 1 (3 10^8)^2 = 9 10¹⁶ J . (Matches III) (B) For m = 1 mg = 10⁻⁶ kg : E = 10⁻⁶ (3 10^8)^2 = 9 10¹⁰ J . (Matches IV) (C) 1 atomic mass unit (u) is standardly equivalent to 931.5 MeV . (Matches I) (D) The rest mass energy of an electron is standardly 0.511 MeV . (Matches II) Therefore, the correct matching is (A)-(III), (B)-(IV), (C)-(I), (D)-(II). Answer: (A)-(III), (B)-(IV), (C)-(I), (D)-(II)