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NEET
Exam
NEET
Subject
Physics
Chapter
Nuclear Physics

NEET · Physics · Nuclear Physics

Match the mass quantities in List-I with their corresponding energy...

Match the mass quantities in List-I with their corresponding energy equivalents in List-II.

List-IList-II
(A) 1 kg1 \text{ kg}(I) 931.5 MeV931.5 \text{ MeV}
(B) 1 mg1 \text{ mg}(II) 0.511 MeV0.511 \text{ MeV}
(C) 1 atomic mass unit (u)1 \text{ atomic mass unit (u)}(III) 9×1016 J9 \times 10^{16} \text{ J}
(D) Mass of an electron(IV) 9×1010 J9 \times 10^{10} \text{ J}

Choose the correct answer from the options given below:

Options

  1. A(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
  2. B(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
  3. C(A)-(III), (B)-(IV), (C)-(II), (D)-(I)
  4. D(A)-(III), (B)-(I), (C)-(IV), (D)-(II)

Correct answer

A. (A)-(III), (B)-(IV), (C)-(I), (D)-(II)

Step-by-step solution

According to Einstein's mass-energy equivalence, E=mc2E = mc^2.

(A) For m=1 kgm = 1 \text{ kg}:
E=1×(3×108)2=9×1016 JE = 1 \times (3 \times 10^8)^2 = 9 \times 10^{16} \text{ J}. (Matches III)

(B) For m=1 mg=10−6 kgm = 1 \text{ mg} = 10^{-6} \text{ kg}:
E=10−6×(3×108)2=9×1010 JE = 10^{-6} \times (3 \times 10^8)^2 = 9 \times 10^{10} \text{ J}. (Matches IV)

(C) 1 atomic mass unit (u)1 \text{ atomic mass unit (u)} is standardly equivalent to 931.5 MeV931.5 \text{ MeV}. (Matches I)

(D) The rest mass energy of an electron is standardly 0.511 MeV0.511 \text{ MeV}. (Matches II)

Therefore, the correct matching is (A)-(III), (B)-(IV), (C)-(I), (D)-(II).

Answer: (A)-(III), (B)-(IV), (C)-(I), (D)-(II)
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