A deuteron is bombard on _8 O^ 16 nuclei than α -particle is emitted then the product nuclei is:

Correct answer: D. _7 ~N^ 14 _8 O^ 16 + _1 H^1 _2 X^4+ _2 He^4 Use conservation of charge and mass The conservation of mass number gives 16+2=A+4 A=14 The conservation of atomic number gives. 8+1=2+2 2=7 Therefore, _2 X^4 is _7 ~N^ 14

NEET 2002

Exam: NEET
Year: 2002
Subject: Physics
Chapter: Nuclear Physics

NEET 2002 · Physics · Nuclear Physics

A deuteron is bombard on _8 O^ 16 nuclei than α -particle is...

A deuteron is bombard on

{ }_8 \mathrm{O}^{16}

nuclei than

\alpha

-particle is emitted then the product nuclei is:

Options

A ${ }_7 \mathrm{~N}^{13}$
B ${ }_5 \mathrm{~B}^{10}$
C ${ }_4 \mathrm{Be}^9$
D ${ }_7 \mathrm{~N}^{14}$

Correct answer

D. ${ }_7 \mathrm{~N}^{14}$

Step-by-step solution

{ }_8 \mathrm{O}^{16}+{ }_1 \mathrm{H}^1 \longrightarrow{ }_2 \mathrm{X}^4+{ }_2 \mathrm{He}^4

Use conservation of charge and mass The conservation of mass number gives 16+2=A+4 \Rightarrow A=14 The conservation of atomic number gives. 8+1=2+2 \Rightarrow 2=7 Therefore,

{ }_2 \mathrm{X}^4

{ }_7 \mathrm{~N}^{14}

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