NEET2002PhysicsNuclear PhysicsActual
A deuteron is bombard on ₈ O ¹⁶ nuclei than -particle is emitted then the product nuclei is:
Options
- A₇ ~N ¹³
- B₅ ~B ¹⁰
- C₄ Be ^9
- D₇ ~N ¹⁴
Correct answer
D. ₇ ~N ¹⁴
Step-by-step solution
₈ O ¹⁶+ ₁ H ^1 ₂ X ^4+ ₂ He ^4 Use conservation of charge and mass The conservation of mass number gives 16+2=A+4 A=14 The conservation of atomic number gives. 8+1=2+2 2=7 Therefore, ₂ X ^4 is ₇ ~N ¹⁴