NEETChemistryChemical Bonding and Molecular Structure
Match each of the diatomic molecules in Column I with its property/properties in Column II.
Options
- A(A) q,t, (B) s,t, (C) r,t, (D) p,q,s
- B(A) p,q,s,t, (B) p,s,t, (C) p,q, (D) r,s
- C(A) p,r,t, (B) s,t, (C) p,q,r, (D) p,r,s
- D(A) p,q,s,t, (B) p,s,t, (C) p,q, (D) r,s
Correct answer
C. (A) p,r,t, (B) s,t, (C) p,q,r, (D) p,r,s
Step-by-step solution
- A. (B₂ ) : Has two unpaired electrons, making it p. Paramagnetic. The close energy levels of (2 s ) and (2 p ) orbitals lead to ( t.s - p ) mixing. - B. ( N _ 2 ) : Has a bond order of ( 3 ), so its bond order is ( s ). ( 2 ). It also has ( t . s - p ) mixing and can gain electrons, so it r. Undergoes reduction. - C. (O₂ ) : Has two unpaired electrons, making it p. Paramagnetic. Its bond order is 2 , so it's ( s ). ( ) 2. With electrons in antibonding orbitals, it can lose electrons, thus q. Undergoing oxidation.