NEETChemistryChemical Bonding and Molecular Structure
Match List- I with List- II . List- I List- II (Molecule) (Bond order) (a) Ne 2 (i) 1 (b) N 2 (ii) 2 (c) F 2 (iii) 0 (d) O 2 (iv) 3 Choose the correct answer from the options given below:
Options
- Aa → ii , b → i , c → iv , d → iii
- Ba → iii , b → iv , c → i , d → ii
- Ca → i , b → ii , c → iii , d → iv
- Da → iv , b → iii , c → ii , d → i
Correct answer
B. a → iii , b → iv , c → i , d → ii
Step-by-step solution
Bond order = 1 2 ​ (number of electrons in bonding MO - number of electrons in anti-bonding MO) (a) Ne 2 = Total e Θ = 20 B.O. = 10 - 10 2 = 0 (b) N 2 = Total e ⊝ = 14 B.O. = 10 - 4 2 = 3 (c) F 2 = Total e ⊝ = 18 B.O. = 10 - 8 2 = 1 (d) O 2 = Total e ⊝ = 16 B.O. = 10 - 6 2 = 2