NEETChemistryChemical Bonding and Molecular Structure
Match the following: The correct answer is array llllllll A & B & C & D & A & B & C & D array
Options
- Aarray llll V & I & III & II array
- Barray llll V & II & I & IV array
- Carray llll III & V & I & IV array
- Darray llll III &IV & I & II array
Correct answer
D. array llll III &IV & I & II array
Step-by-step solution
(A) Trigonal planar (III) BF ₃ , because boron has three (3) valence electrons which are involved in formation of three sigma ( ) bonds with 3 ~F -atoms and has no lone pair (l p) of electrons. (B) Tetrahedral (IV) CCl ₄ , because carbon has four (4) valence electrons which are involved in formation of four sigma ( ) bonds with 4 Cl -atoms and has no lp of electrons. (C) Trigonal bipyramidal (I) PCl ₅ , because phosphorus has five valence electrons which are involved in formation of five sigma ( ) bonds with 5 Cl a