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NEETChemistryChemical Bonding and Molecular Structure

Match the following: The correct answer is array llllllll A & B & C & D & A & B & C & D array

Options

  1. Aarray llll V & I & III & II array
  2. Barray llll V & II & I & IV array
  3. Carray llll III & V & I & IV array
  4. Darray llll III &IV & I & II array

Correct answer

D. array llll III &IV & I & II array

Step-by-step solution

(A) Trigonal planar (III) BF ₃ , because boron has three (3) valence electrons which are involved in formation of three sigma ( ) bonds with 3 ~F -atoms and has no lone pair (l p) of electrons. (B) Tetrahedral (IV) CCl ₄ , because carbon has four (4) valence electrons which are involved in formation of four sigma ( ) bonds with 4 Cl -atoms and has no lp of electrons. (C) Trigonal bipyramidal (I) PCl ₅ , because phosphorus has five valence electrons which are involved in formation of five sigma ( ) bonds with 5 Cl a

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