NEETChemistryChemical Bonding and Molecular Structure
Match the following The correct answer is
Options
- AA-III, B-I, C-II, D-IV
- BA-IV, B-III, C-I, D-II
- CA-III, B-I, C-IV, D-II
- DA-III, B-IV, C-II, D-I
Correct answer
D. A-III, B-IV, C-II, D-I
Step-by-step solution
Sn belongs to group 14 and has four valence electrons out of which two are used for forming two Sn - Cl bonds and the remaining two form a lone pair of electrons. Thus, SnCl ₂ will be angular or bent in shape. NH ₃ has three bond pairs and one lone pair so it acquires a trigonal pyramidal shape. I ₃ ⁻ has a linear geometry as the two bond pairs lie along a straight line while the three lone pairs form the equatorial geometry. SO ₃ has three bond pairs only so it forms a trigonal planar shape. Thus, A III , B IV , C