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NEETChemistryChemical Bonding and Molecular Structure

Discuss the shape of BCl 3 using the VSEPR model.

Options

  1. ABCl 3 has a linear shape with a bond angle of 180 degrees.
  2. BBCl 3 has a trigonal planar shape with a bond angle of 120 degrees.
  3. CBCl 3 has a bent or V-shaped geometry with a bond angle of less than 109.5 degrees.
  4. DBCl 3 has a trigonal pyramidal shape with a bond angle of approximately 109.5 degrees.

Correct answer

B. BCl 3 has a trigonal planar shape with a bond angle of 120 degrees.

Step-by-step solution

Correct Option is : (B) BCl 3 has a trigonal planar shape with a bond angle of 120 degrees.

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