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NEETChemistryChemical Bonding and Molecular Structure

Match List-I with List-II. List-I List-II (A) Sigma ( ) molecular orbital (I) Symmetrical around the internuclear axis (B) Pi ( ) molecular orbital (II) Zero electron density along the internuclear axis (C) Bonding molecular orbital (III) Formed by addition of wave functions (D) Antibonding molecular orbital (IV) Has a nodal plane between the nuclei Choose the correct answer from the options given below:

Options

  1. A(A)-(II), (B)-(I), (C)-(III), (D)-(IV)
  2. B(A)-(I), (B)-(II), (C)-(IV), (D)-(III)
  3. C(A)-(I), (B)-(IV), (C)-(III), (D)-(II)
  4. D(A)-(I), (B)-(II), (C)-(III), (D)-(IV)

Correct answer

D. (A)-(I), (B)-(II), (C)-(III), (D)-(IV)

Step-by-step solution

According to Molecular Orbital Theory: Sigma ( ) molecular orbitals are symmetrical around the internuclear axis. Pi ( ) molecular orbitals are not symmetrical around the internuclear axis and have zero electron density along the internuclear axis. Bonding molecular orbitals are formed by the constructive interference (addition) of electron wave functions ( _A + _B ). Antibonding molecular orbitals are formed by the destructive interference (subtraction) of electron wave functions ( _A - _B ) and possess a nodal pl

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