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NEETChemistryChemical Bonding and Molecular Structure

Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A): The H-O-H bond angle in water is smaller than the H-N-H bond angle in ammonia. Reason (R): According to VSEPR theory, the repulsion between two lone pairs of electrons is greater than the repulsion between a lone pair and a bond pair. In the light of the above statements, choose the most appropriat

Options

  1. ABoth (A) and (R) are correct and (R) is the correct explanation of (A)
  2. BBoth (A) and (R) are correct but (R) is not the correct explanation of (A)
  3. C(A) is correct but (R) is not correct
  4. D(A) is not correct but (R) is correct

Correct answer

A. Both (A) and (R) are correct and (R) is the correct explanation of (A)

Step-by-step solution

In water ( H ₂ O ), the central oxygen atom has 2 bond pairs and 2 lone pairs. In ammonia ( NH ₃ ), the central nitrogen atom has 3 bond pairs and 1 lone pair. According to the postulates of VSEPR theory, the order of repulsion between electron pairs is: lone pair - lone pair > lone pair - bond pair > bond pair - bond pair. Because water has two lone pairs, the strong lone pair - lone pair repulsion compresses the H-O-H bond angle to approximately 104.5^ . Ammonia has only one lone pair, so the lone pair - bond pai

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