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NEETChemistryChemical Bonding and Molecular Structure

Match List-I with List-II. List-I (Molecule) List-II (Octet configuration) (A) NO ₂ (I) Complete octet (B) BCl ₃ (II) Incomplete octet (C) H ₂ O (III) Expanded octet (D) SF ₆ (IV) Odd electron molecule Choose the correct answer from the options given below:

Options

  1. A(A)-(II), (B)-(IV), (C)-(I), (D)-(III)
  2. B(A)-(IV), (B)-(II), (C)-(I), (D)-(III)
  3. C(A)-(IV), (B)-(I), (C)-(II), (D)-(III)
  4. D(A)-(II), (B)-(II), (C)-(I), (D)-(III)

Correct answer

B. (A)-(IV), (B)-(II), (C)-(I), (D)-(III)

Step-by-step solution

In NO ₂ , nitrogen has an unpaired electron, making it an odd electron molecule. In BCl ₃ , boron has 3 valence electrons and forms 3 single bonds, resulting in 6 electrons around the central atom (incomplete octet). In H ₂ O , oxygen has 6 valence electrons, forms 2 single bonds, and has 2 lone pairs, resulting in 8 electrons around the central atom (complete octet). In SF ₆ , sulfur has 6 valence electrons and forms 6 single bonds, resulting in 12 electrons around the central atom (expanded octet). Therefore, the

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