NEETChemistryChemical Bonding and Molecular Structure
Match List-I with List-II: List-I (Species) List-II (Properties) (A) N ₂^+ (i) Bond order = 1 , Paramagnetic (B) O ₂^- (ii) Bond order = 2 , Diamagnetic (C) C ₂ (iii) Bond order = 2.5 , Paramagnetic (D) B ₂ (iv) Bond order = 1.5 , Paramagnetic Choose the correct answer from the options given below:
Options
- A(A)-(ii), (B)-(iv), (C)-(iii), (D)-(i)
- B(A)-(iv), (B)-(iii), (C)-(ii), (D)-(i)
- C(A)-(iii), (B)-(iv), (C)-(i), (D)-(ii)
- D(A)-(iii), (B)-(iv), (C)-(ii), (D)-(i)
Correct answer
D. (A)-(iii), (B)-(iv), (C)-(ii), (D)-(i)
Step-by-step solution
The electronic configuration and properties of the given species are deduced using Molecular Orbital Theory (MOT): 1. N ₂^+ ( 13 electrons): 1s^2 ^ * 1s^2 2s^2 ^ * 2s^2 2p_x^2 = 2p_y^2 2p_z^1 . Bond order = 9 - 4 2 = 2.5 . It has one unpaired electron, hence it is paramagnetic. (A) matches with (iii). 2. O ₂^- ( 17 electrons): 1s^2 ^ * 1s^2 2s^2 ^ * 2s^2 2p_z^2 2p_x^2 = 2p_y^2 ^ * 2p_x^2 = ^ * 2p_y^1 . Bond order = 10 - 7 2 = 1.5 . It has one unpaired electron, hence it is paramagnetic. (B) matches with (iv). 3. C