NEETChemistryChemical Bonding and Molecular Structure
Match List-I with List-II: List-I (Chemical Species) List-II (Lone pairs on central atom) (A) SO ₄²⁻ (I) 1 (B) XeOF ₄ (II) 2 (C) BrF ₃ (III) 3 (D) I ₃⁻ (IV) 0 Choose the correct answer from the options given below:
Options
- A(A)-(II), (B)-(IV), (C)-(I), (D)-(III)
- B(A)-(IV), (B)-(II), (C)-(III), (D)-(I)
- C(A)-(IV), (B)-(I), (C)-(III), (D)-(II)
- D(A)-(IV), (B)-(I), (C)-(II), (D)-(III)
Correct answer
D. (A)-(IV), (B)-(I), (C)-(II), (D)-(III)
Step-by-step solution
The number of lone pairs on the central atom can be calculated by subtracting the number of electrons shared in bonds from the total valence electrons (including charge) and dividing by 2. (A) SO ₄²⁻ : Central S atom has 6 valence electrons + 2 (from negative charge) = 8 available electrons. Four oxygen atoms are divalent and consume 4 2 = 8 electrons. Remaining electrons = 0. Lone pairs = 0. (B) XeOF ₄ : Central Xe atom has 8 valence electrons. One oxygen atom consumes 2 electrons and four fluorine atoms consume 4