NEETChemistryChemical Bonding and Molecular Structure
Given below are two lists: List I (Molecule) List II (Property & HOMO) (A) B ₂ (I) Diamagnetic, highest occupied molecular orbital is _ 2p_z (B) C ₂ (II) Paramagnetic, highest occupied molecular orbitals are _ 2p_x ^* and _ 2p_y ^* (C) N ₂ (III) Paramagnetic, highest occupied molecular orbitals are _ 2p_x and _ 2p_y (D) O ₂ (IV) Diamagnetic, highest occupied molecular orbitals are _ 2p_x and _ 2p_y Choose the correct
Options
- AA-IV, B-III, C-I, D-II
- BA-III, B-I, C-IV, D-II
- CA-III, B-IV, C-I, D-II
- DA-I, B-IV, C-III, D-II
Correct answer
C. A-III, B-IV, C-I, D-II
Step-by-step solution
The molecular orbital configurations are determined by the total number of electrons: B ₂ (10 electrons): _ 1s ^2 _ 1s ^ *2 _ 2s ^2 _ 2s ^ *2 _ 2p_x ^1 = _ 2p_y ^1 . According to Hund's rule, it has two unpaired electrons, making it paramagnetic. The highest occupied molecular orbitals (HOMO) are _ 2p_x and _ 2p_y . Thus, (A) matches (III). C ₂ (12 electrons): _ 1s ^2 _ 1s ^ *2 _ 2s ^2 _ 2s ^ *2 _ 2p_x ^2 = _ 2p_y ^2 . All electrons are paired, making it diamagnetic. The HOMO are _ 2p_x and _ 2p_y . Thus, (B) match