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NEETChemistryChemical Bonding and Molecular Structure

Which of the following molecules contains exactly two bonds and has carbon atoms in both sp and sp^2 hybridization states, but no sp^3 hybridized carbon atom?

Options

  1. APropyne
  2. BButa-1,3-diene
  3. CPropadiene
  4. DBut-1-en-3-yne

Correct answer

C. Propadiene

Step-by-step solution

Let us analyze the given molecules for their number of bonds and the hybridization of their carbon atoms: Propyne ( CH₃-C CH ): Contains one triple bond, hence two bonds. The carbon atoms are sp^3 , sp , and sp hybridized. It contains an sp^3 carbon, so it does not match the criteria. Buta-1,3-diene ( CH₂=CH-CH=CH₂ ): Contains two double bonds, hence two bonds. All four carbon atoms are sp^2 hybridized. It lacks an sp hybridized carbon. Propadiene ( CH₂=C=CH₂ ): Contains two double bonds, hence two bonds. The termi

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