NEETChemistryChemical Bonding and Molecular Structure
Which of the following molecules contains exactly two bonds and has carbon atoms in both sp and sp^2 hybridization states, but no sp^3 hybridized carbon atom?
Options
- APropyne
- BButa-1,3-diene
- CPropadiene
- DBut-1-en-3-yne
Correct answer
C. Propadiene
Step-by-step solution
Let us analyze the given molecules for their number of bonds and the hybridization of their carbon atoms: Propyne ( CH₃-C CH ): Contains one triple bond, hence two bonds. The carbon atoms are sp^3 , sp , and sp hybridized. It contains an sp^3 carbon, so it does not match the criteria. Buta-1,3-diene ( CH₂=CH-CH=CH₂ ): Contains two double bonds, hence two bonds. All four carbon atoms are sp^2 hybridized. It lacks an sp hybridized carbon. Propadiene ( CH₂=C=CH₂ ): Contains two double bonds, hence two bonds. The termi