NEETChemistryChemical Bonding and Molecular Structure
Match List I with List II. List I (Property) List II (Decreasing Order) (A) Dipole moment (I) ClF ₃ SF ₄ IF ₇ (B) Bond angle (II) CO O ₂ F ₂ (C) Number of lone pairs on central atom (III) H ₂ O H ₂ S H ₂ Se (D) Bond order (IV) NH ₃ NF ₃ BF ₃ Choose the correct answer from the options given below:
Options
- A(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
- B(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
- C(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
- D(A)-(I), (B)-(II), (C)-(IV), (D)-(III)
Correct answer
A. (A)-(IV), (B)-(III), (C)-(I), (D)-(II)
Step-by-step solution
(A) Dipole moment: NH ₃ (1.47 D) NF ₃ (0.23 D) BF ₃ (0 D). In NH ₃ , the orbital dipole and bond dipoles are in the same direction, whereas in NF ₃ they oppose each other. BF ₃ is symmetrical with zero dipole moment. (B) Bond angle: H ₂ O (104.5 ^ ) H ₂ S (92 ^ ) H ₂ Se (91 ^ ). As the electronegativity of the central atom decreases down the group, bond pairs move away from the central atom, decreasing the bond angle. (C) Number of lone pairs on central atom: ClF ₃ has 2 lone pairs, SF ₄ has 1 lone pair, and IF ₇ h