NEETChemistryGeneral Organic Chemistry
Match List I with List II: List I List II A. Isopropyl cation I. Highly unstable due to positive charge on sp hybridized carbon B. Allyl cation II. Stabilized by hyperconjugation involving 6 -hydrogens C. Benzyl cation III. Stabilized by resonance with one bond D. Vinyl cation IV. Stabilized by resonance with a benzene ring Choose the correct answer from the options given below:
Options
- AA-III, B-II, C-IV, D-I
- BA-II, B-IV, C-III, D-I
- CA-I, B-III, C-IV, D-II
- DA-II, B-III, C-IV, D-I
Correct answer
D. A-II, B-III, C-IV, D-I
Step-by-step solution
Isopropyl cation (CH₃)₂CH^+ has 6 -hydrogens, so it is stabilized by hyperconjugation (A II). Allyl cation CH₂=CH-CH₂^+ is stabilized by resonance involving one adjacent bond (B III). Benzyl cation C₆H₅CH₂^+ is stabilized by extensive resonance delocalization with the benzene ring (C IV). Vinyl cation CH₂=CH^+ has the positive charge on an electronegative sp hybridized carbon, making it highly unstable (D I). Therefore, the correct matching is A-II, B-III, C-IV, D-I. Answer: A-II, B-III, C-IV, D-I