In Duma's method of estimation of nitrogen, 0.35 g of an organic compound gave 55 mL of nitrogen collected at 300 K temperature and 715 mm pressure. The percentage composition of nitrogen in the compound would be (Aqueous tension at 300 ~K =15 ~mm )

Step-by-step solution

aligned & p₁ V₁ T₁ = p₂ V₂ T₂ & or ( - ₁ ) T₁ V₁= p₂ V₂ T₂ aligned where, p₁= - ₁ =715 ~mm (pressure at which N ₂ collected). aligned & ₁= aqueous tension of water =15 ~mm & t₁=t+273=300 ~K & V₁=55 ~mL = Volume of moist nitrogen in & nitrometer & ₂= pressure of N ₂ at STP =760 ~mm & t₂= temperature of N ₂ at STP =273 ~K & V₂= ? aligned V₂= (715-15) 300 55 273 760 =46.098 ~mL % of nitrogen in the given compound aligned & = 28 22400 V₂ W 100= 28 22400 46.098 0.35 100 & =16.45 % aligned