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NEETChemistryp Block Elements (Group 15, 16, 17 & 18)

What is the formula of the xenon fluoride that can be prepared by the interaction of XeF 4 and O 2 F 2 at 143 K?

Options

  1. AXeF 2
  2. BXeF 4
  3. CXeF 6
  4. DXe 2 F 12

Correct answer

C. XeF 6

Step-by-step solution

XeF 6 can be prepared by the interaction of XeF 4 and O 2 F 2 at 143 K.

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