NEETChemistryp Block Elements (Group 15, 16, 17 & 18)
When metal X is treated with sodium hydroxide, a white precipitate (A) is obtained, which is soluble in excess of NaOH to give soluble complex (B). Compound (A) is soluble in dilute HCl to form compound (C). The compound (A) when heated strongly gives (D), which is used to extract metal. Identify (X), (A), (B), (C), and (D). Write suitable equations to support their identities.
Options
- AX = Zinc (Zn), A = Zinc Hydroxide (Zn(OH)₂), B = Sodium Zincate (Na₂ZnO₂), C = Zinc Chloride (ZnCl₂), D = Zinc
- BX = Aluminium (Al), A = Aluminium Hydroxide (Al(OH)₃), B = Sodium Aluminate (NaAlO₂), C = Aluminium Chloride (
- CX = Calcium (Ca), A = Calcium Hydroxide (Ca(OH)₂), B = Sodium Calciumate (Na₂CaO₂), C = Calcium Chloride (CaCl
- DX = Iron (Fe), A = Iron Hydroxide (Fe(OH)₃), B = Sodium Ironate (Na₂FeO₂), C = Iron Chloride (FeCl₃), D = Iron
Correct answer
B. X = Aluminium (Al), A = Aluminium Hydroxide (Al(OH)₃), B = Sodium Aluminate (NaAlO₂), C = Aluminium Chloride (
Step-by-step solution
Correct Option is : (B) X = Aluminium (Al), A = Aluminium Hydroxide (Al(OH)₃), B = Sodium Aluminate (NaAlO₂), C = Aluminium Chloride (AlCl₃), D = Alumina (Al₂O₃)