NEETChemistryp Block Elements (Group 15, 16, 17 & 18)
If 10 moles of dinitrogen and 15 moles of dihydrogen are mixed in a closed vessel to synthesize ammonia, what is the maximum number of moles of ammonia that can be formed?
Options
- A20
- B15
- C5
- D10
Correct answer
D. 10
Step-by-step solution
The balanced chemical equation for the synthesis of ammonia is: N ₂( g ) + 3 H ₂( g ) 2 NH ₃( g ) According to the reaction, 1 mole of N ₂ requires 3 moles of H ₂ . For 10 moles of N ₂ , the required moles of H ₂ = 10 3 = 30 moles . Since only 15 moles of H ₂ are available, H ₂ is the limiting reagent. The amount of product formed depends on the limiting reagent. From the balanced equation, 3 moles of H ₂ produce 2 moles of NH ₃ . Therefore, 15 moles of H ₂ will produce 2 3 15 = 10 moles of NH ₃ . Answer: 10