NEETChemistryp Block Elements (Group 15, 16, 17 & 18)
Match List-I with List-II: List-I (Reagents) List-II (Observation) (A) NaCl + conc. H₂ SO₄ (I) Greenish-yellow gas (B) NaCl + MnO₂ + conc. H₂ SO₄ (II) Reddish-brown gas (C) NaBr + MnO₂ + conc. H₂ SO₄ (III) Violet vapors (D) NaI + MnO₂ + conc. H₂ SO₄ (IV) Colorless pungent gas Choose the correct answer from the options given below:
Options
- A(A)-(IV), (B)-(I), (C)-(II), (D)-(III)
- B(A)-(IV), (B)-(I), (C)-(III), (D)-(II)
- C(A)-(I), (B)-(IV), (C)-(II), (D)-(III)
- D(A)-(IV), (B)-(II), (C)-(I), (D)-(III)
Correct answer
A. (A)-(IV), (B)-(I), (C)-(II), (D)-(III)
Step-by-step solution
When NaCl is heated with concentrated H₂ SO₄ , hydrogen chloride (HCl) gas is evolved, which is a colorless gas with a pungent odor. Thus, (A) matches (IV). When NaCl is heated with MnO₂ and concentrated H₂ SO₄ , MnO₂ acts as an oxidizing agent and oxidizes the chloride ions to chlorine (Cl₂ ) gas, which is a greenish-yellow gas. Thus, (B) matches (I). Similarly, heating NaBr with MnO₂ and concentrated H₂ SO₄ produces bromine (Br₂ ) gas, which evolves as reddish-brown vapors. Thus, (C) matches (II). Heating NaI wit