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NEETChemistryp Block Elements (Group 15, 16, 17 & 18)

Match List I with List II: List I List II (A) HNO₂ (I) Strongest reducing agent among group 15 hydrides (B) BiH₃ (II) Undergoes disproportionation in acidic medium (C) N₂O₅ (III) +3 oxidation state is more stable than +5 (D) Bismuth (IV) Most acidic oxide among group 15 Choose the correct answer from the options given below:

Options

  1. A(A)-(II), (B)-(I), (C)-(IV), (D)-(III)
  2. B(A)-(II), (B)-(III), (C)-(IV), (D)-(I)
  3. C(A)-(IV), (B)-(I), (C)-(II), (D)-(III)
  4. D(A)-(I), (B)-(II), (C)-(III), (D)-(IV)

Correct answer

A. (A)-(II), (B)-(I), (C)-(IV), (D)-(III)

Step-by-step solution

(A) HNO₂ undergoes disproportionation in an acidic medium to form HNO₃ and NO . (B) BiH₃ is the strongest reducing agent among Group 15 hydrides because the E-H bond dissociation enthalpy decreases down the group. (C) N₂O₅ is the most acidic oxide among Group 15 elements, as acidic character of oxides decreases down the group. (D) For Bismuth, the +3 oxidation state is much more stable than the +5 oxidation state due to the prominent inert pair effect. Therefore, the correct matching is (A)-(II), (B)-(I), (C)-(IV),

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