NEETChemistryp Block Elements (Group 15, 16, 17 & 18)
Match the species in List-I with their characteristic bonding features in List-II. List-I List-II (A) N ₂ (I) p - p multiple bond (B) R ₃ P = CH ₂ (II) d - p bond (C) PR ₃ complex with transition metals (III) d - d bond (D) P ₄ (IV) Only single bonds Choose the correct answer from the options given below:
Options
- A(A)-(I), (B)-(II), (C)-(III), (D)-(IV)
- B(A)-(II), (B)-(I), (C)-(III), (D)-(IV)
- C(A)-(I), (B)-(III), (C)-(II), (D)-(IV)
- D(A)-(I), (B)-(II), (C)-(IV), (D)-(III)
Correct answer
A. (A)-(I), (B)-(II), (C)-(III), (D)-(IV)
Step-by-step solution
Nitrogen lacks d-orbitals in its valence shell and its small size allows it to form strong p - p multiple bonds. Thus, N ₂ exists as a diatomic molecule with a triple bond. Heavier elements like phosphorus have vacant d-orbitals. In compounds like R ₃ P = CH ₂ , phosphorus utilizes its d-orbitals to form a d - p bond with carbon. Phosphorus can also act as a -acceptor ligand, forming d - d back-bonds with the filled d-orbitals of transition metals in PR ₃ complexes. Due to their larger size and diffuse orbitals, he