NEETChemistryp Block Elements (Group 15, 16, 17 & 18)
Match List-I with List-II: List-I List-II (A) Diamond (I) sp ^2 hybridized, pure form without dangling bonds (B) Graphite (II) sp ^3 hybridized, rigid 3D network (C) Fullerene (III) sp ^2 hybridized, layered structure with van der Waals forces (D) Carbon black (IV) Amorphous form obtained by burning hydrocarbons in limited supply of air Choose the correct answer from the options given below:
Options
- A(A) - (II), (B) - (I), (C) - (III), (D) - (IV)
- B(A) - (II), (B) - (III), (C) - (I), (D) - (IV)
- C(A) - (III), (B) - (II), (C) - (I), (D) - (IV)
- D(A) - (II), (B) - (III), (C) - (IV), (D) - (I)
Correct answer
B. (A) - (II), (B) - (III), (C) - (I), (D) - (IV)
Step-by-step solution
Diamond has a rigid 3D network of sp ^3 hybridized carbon atoms. Graphite has a layered structure where each layer consists of planar hexagonal rings of sp ^2 hybridized carbon atoms, and the layers are held together by weak van der Waals forces. Fullerenes are the purest form of carbon because they have smooth structure without dangling bonds, and their carbon atoms are sp ^2 hybridized. Carbon black is an amorphous form of carbon obtained by burning hydrocarbons in a limited supply of air. Answer: (A) - (II), (B)