What is the number of moles of ammonia produced when 56 g of nitrogen gas reacts completely with excess hydrogen gas in Haber's process?

Step-by-step solution

The balanced chemical equation for Haber's process is: N ₂( g ) + 3 H ₂( g ) 2 NH ₃( g ) First, calculate the number of moles of nitrogen gas ( N ₂ ): Molar mass of N ₂ = 28 g mol ⁻¹ Moles of N ₂ = 56 g 28 g mol ⁻¹ = 2 moles According to the stoichiometry of the reaction, 1 mole of N ₂ produces 2 moles of NH ₃ . Therefore, 2 moles of N ₂ will produce 2 2 = 4 moles of NH ₃ . Answer: 4