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NEET2018Chemistryp Block Elements (Group 15, 16, 17 & 18)Actual

Xenon hexafluoride reacts with silica to form a xenon compound X . The oxidation state of xenon in X is

Options

  1. A+2
  2. B+4
  3. C+6
  4. D0

Correct answer

C. +6

Step-by-step solution

Xenon hexa fluoride reacts with silica to form XeOF ₄ as 2 XeF ₆+ SiO ₂ 2 XeOF ₄+ SiF ₄ The oxidation state of xenon in XeOF ₄ is +6 as calculated below: Let the oxidation state of Xe is a aligned a +1 (-2)+4 (-1) & =0 a -2-4 & =0 a & =+6 aligned

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