NEET2026ChemistryAlcohols Phenols and EthersActual
In the following reaction sequence, X and Z respectively are : CH ₃ CH ₂ CH ₂- OH + PCl ₅ CH ₃ CH ₂ CH ₂ Cl + X + HCl CH ₃ CH ₂ CH ₂ Cl [ ] alc. KOH Y [( C ₆ H ₅ CO )₂ O ₂] HBr Z
Options
- AX = POCl ₃ ; Z = CH ₃- CH(Br) - CH ₃
- BX = POCl ₃ ; Z = CH ₃ CH ₂ CH ₂- Br
- CX = H ₃ PO ₃ ; Z = CH ₃- CH(Br) - CH ₃
- DX = H ₃ PO ₃ ; Z = CH ₃ CH ₂ CH ₂- Br
Correct answer
B. X = POCl ₃ ; Z = CH ₃ CH ₂ CH ₂- Br
Step-by-step solution
Reaction of primary alcohol with PCl ₅ gives alkyl chloride, POCl ₃ , and HCl . CH ₃ CH ₂ CH ₂ OH + PCl ₅ CH ₃ CH ₂ CH ₂ Cl + POCl ₃ + HCl Thus, X = POCl ₃ . Dehydrohalogenation of 1-chloropropane with alcoholic KOH yields propene. CH ₃ CH ₂ CH ₂ Cl alc. KOH , CH ₃ CH = CH ₂ Thus, Y = CH ₃ CH = CH ₂ . Addition of HBr to propene in the presence of peroxide follows anti-Markovnikov addition. CH ₃ CH = CH ₂ + HBr ( C ₆ H ₅ CO )₂ O ₂ CH ₃ CH ₂ CH ₂ Br Thus, Z = CH ₃ CH ₂ CH ₂ Br . Answer: X = POCl ₃ ; Z = CH ₃ CH ₂ CH