Identify the product formed when ethyl alcohol reacts with H_2SO_4...

When ethyl alcohol is heated with concentrated $\text{H}_2\text{SO}_4$ at $443\text{ K}$, it undergoes intramolecular dehydration to form ethene.

$\text{CH}_3\text{CH}_2\text{OH} \xrightarrow[443\text{ K}]{\text{conc. H}_2\text{SO}_4} \text{CH}_2=\text{CH}_2 + \text{H}_2\text{O}$

At a lower temperature of $413\text{ K}$, intermolecular dehydration occurs to yield ethoxyethane (diethyl ether).

Thus, the product formed at $443\text{ K}$ is ethene.

Answer: Ethene